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`(3)/(8)``(-3)/(4)``(1)/(4)``-2`

Answer :

BSolution :

We have `4y^(3) -8a^(2)yx^(2) - 3ay^(2)x +8x^(3) =0` <br> `rArr 4 ((y)/(x))^(3) -3a ((y)/(x))^(2) -8a^(2) ((y)/(x)) +8 =0` has roots `m_(1),m_(2),m_(3)` <br> `:. m_(1)m_(2)m_(3) =- 2` <br> Given `m_(1)m_(2) =-1` <br> `:. m_(3)=2` <br> `:. 4(2)^(3)-3a(2)^(2) -8a^(2)(2) +8 =0` <br> `rArr 4a^(2) +3a - 10 =0`<br> `:.` Sum of possible values of roots `=(-3)/(4)`